Today I came across an interesting . I had solved the "adaptive" version of the same puzzle but this one has that nice "non-adaptive" twist. I must admit that I struggled for couple of hours to get this right. But when I got it it felt realllllly good! :)
Here's one of the solution (I believe, for some reason, that there are many possible solutions):
Coins are numbered from 1 to 12.
1) Weigh 6,5,7,11 with 8, 9, 10, 12
2) Weigh 2,3,4,8 with 9, 10, 11, 12
3) Weigh 3,6,8,10 with 1,4,7, 9
/ : left tilt
- : no tilt
\ : right tilt
n H : nth coin is heavier than others.
n L : nth coin is lighter than others.
Outcomes:
- - \ : 1 H
- - / : 1 L
- / - : 2 H
- \ - : 2 L
- / / : 3 H
- \ \ : 3 L
- / \ : 4 H
- \ / : 4 L
/ - - : 5 L
\ - - : 5 H
/ - / : 6 H
\ - \ : 6 L
/ - \ : 7 H
\ - / : 7 L
\ / / : 8 H
/ \ \ : 8 L
\ \ \ : 9 H
/ / / : 9 L
/ \ / : 10 H
\ / \ : 10 L
/ \ - : 11 H
\ / - : 11 L
\ \ - : 12 H
/ / - : 12 L
I have rechecked it but if you are interested, check it again and drop a note if there's something wrong.
Yours Sincerely,
